Shell script to perform linear search in an array

#Check whether a number is present or not
echo -n "Enter limit n: "
read n
for((i=0;i<n;i++))
do
 read a[$i]
done
echo ${a[*]}
echo -n "Enter number to be searched: "
read key
pos=0
for((i=0;i<n;i++))
do
  if test $key -eq ${a[$i]}
  then
      pos=`expr $i + 1`
      break;
  fi
done
if test $i -ge $n
then
  echo "Number not found"
else
  echo "Number [$key] found at position $pos"
fi




OUTPUT
Safi>bash numsrch.sh
Enter limit n: 5
7
6
8
5
9
7 6 8 5 9
Enter number to be searched: 7
Number [7] found at position 1