Sum between 5 and 10

The program must accept N integers as the input. The program must traverse the given integers and if the integer 5 is encountered then the following integers must be added till the integer 10 occurs. Finally, the program must print the total sum as the output.

Boundary Condition(s):
1 <= N <= 1000

Input Format:
The first line contains N.
The second line contains N integers separated by space(s).

Output Format:
The first line contains the sum as per the given conditions.

Example Input/Output 1:
Input:
9
2 5 3 2 10 3 10 5 4
Output:
9
Explanation:
The integer 5 occurs at position 2 and the immediate next integer value 10 occurs at position 5. There are two integers (3 and 2) between them which are added to 5.
The next integer value 5 occurs at position 8 the integers after 5 is 4 which is also added to the result.
Hence the output is 9

Program
#include<stdio.h>
#include <stdlib.h>

int main()
{
   int N,A[1000],i,j=0,temp=0;
   scanf("%d",&N);
   for(i=0;i<N;i++)
      scanf("%d",&A[i]);
   for(i=0;j<N;)
   {
       if(A[i]==5)
       {
          while(A[++i]!=10)
          {
              temp+=A[i];
              if (i>=N)
              break;
          }      
        }
       j=++i;
   }      
   printf("%d",temp);

}

Output
Input:
8
1 5 5 12 10 5 6 10
Output:
23