The program must accept a string S which has alphabets and digits as the input. The program must find the sum of all digits as D in the input string S. Then the program must print the alphabets which are D positions away from the alphabets in the string S.
Example
Input
435acl
The digits are 4,3,5 and their sum D=12
Output
mox
The alphabets in the input are a, c, l
a+12 = m c+12 = o l+12 = x
Program
#include <stdio.h>
#include <ctype.h>
int main()
{
int D=0,i,c=0;
char S[100];
scanf("%s",S);
for(i=0;S[i]!='\0';i++)
if (isdigit(S[i]))
{
D+=S[i]-48;
}
D=D%26;
for(i=0;S[i]!='\0';i++)
{
if (isalpha(S[i]))
{
S[i]=tolower(S[i]);
c=D+S[i];
if(c>122)
{
c=96+(c-122);
}
printf("%c",c);
}
}
}
OUTPUT
Example
Input
435acl
The digits are 4,3,5 and their sum D=12
Output
mox
The alphabets in the input are a, c, l
a+12 = m c+12 = o l+12 = x
Program
#include <stdio.h>
#include <ctype.h>
int main()
{
int D=0,i,c=0;
char S[100];
scanf("%s",S);
for(i=0;S[i]!='\0';i++)
if (isdigit(S[i]))
{
D+=S[i]-48;
}
D=D%26;
for(i=0;S[i]!='\0';i++)
{
if (isalpha(S[i]))
{
S[i]=tolower(S[i]);
c=D+S[i];
if(c>122)
{
c=96+(c-122);
}
printf("%c",c);
}
}
}
OUTPUT
1121ZU
ez
No comments:
Post a Comment